Using the equation: f = μN 4 = μ(2)(10) μ = 0.2
Using the conservation of momentum: m₁v₁ + m₂v₂ = m₁v'₁ + m₂v'₂ 2(5) + 0 = 2v'₁ + 3v'₂
Using Newton's second law: F - f = ma 10 - f = 2(3) f = 4 N
A particle moves along a straight line with an initial velocity of 10 m/s. It accelerates uniformly at 2 m/s² for 5 seconds. Find the final velocity and displacement.
A 5 kg block is lifted vertically upwards from the ground to a height of 10 m. Find the gain in potential energy.
News 25th Apr, 2025: Tablecruncher goes Open Source!
Using the equation: f = μN 4 = μ(2)(10) μ = 0.2
Using the conservation of momentum: m₁v₁ + m₂v₂ = m₁v'₁ + m₂v'₂ 2(5) + 0 = 2v'₁ + 3v'₂
Using Newton's second law: F - f = ma 10 - f = 2(3) f = 4 N
A particle moves along a straight line with an initial velocity of 10 m/s. It accelerates uniformly at 2 m/s² for 5 seconds. Find the final velocity and displacement.
A 5 kg block is lifted vertically upwards from the ground to a height of 10 m. Find the gain in potential energy.
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Dec 20, 2022
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The completely new version 2 for Tablecruncher is due this autumn.